Question: Consider the following C code: main ( ) { int A [ 2 ] [ 2 ] [ 3 ] ; int i , j

Consider the following C code:
main (){
int A[2][2][3];
int i,j,k,x;
x=0;
for (k=0; k<3; k++){
for (j=0; j<2; j++){
for (i=0; i<2; i++){
x++;
A[i][j][k]= x;
}}}
x=-1;
when row major is used
A[0,0,0]=1 A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[1,1,2]=12
when column major is used
A[0,0,0]=1 A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[,,]= A[1,1,2]=12
}
Consider the consecutive blocks of memory given above on the right, where each block can keep an integer value. Assuming that A[0,0,0] is stored in the first block, give the elements of the array A that will be stored in these consecutive blocks, together with their value, just before the statement x=-1 is executed.

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