Question: Consider the following formula. n-1 sin(x) dx = ~ sin - 1(x) cos(x) + sin? - 2(x) dx n n Use the formula to find

Consider the following formula. n-1 sin"(x) dx = ~ sin" - 1(x) cos(x) + sin? - 2(x) dx n n Use the formula to find the integral. (Remember the constant of integration.) sin (x) dxcos 3x - 3 sin x cos x - 9 cos x + C 15 Check your answer by taking the derivative.( sin x dex = - sin a loss + n -) in ( sin 2 - 2 ( sinsuda here me s ( sinsuda = - sini los 4( sin 3 x did 5 for ( sin bu due n2 3 Ssings dre = + 2 s sinn du 3 3 = - Sin u Cosa _ 2 los + C 3 3 -" ( sin Sudd = - sinn cosu sinzu cosu _ 2 Losud + C S 3 3 = - sincosu - 4sinbecos - 8 cos + C 5 IS 15 = - 3 sinn cost - 4 sinha cos - 8 costd C working everything interms of losings and simplifyry, we get Ssinsx du = - 1 cos v + 2 Cos'x - Cosm + C

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