Consider the following method that divides an integer by 2: method DivideBy2(n: int) returns (x: int)...
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Consider the following method that divides an integer by 2: method DivideBy2(n: int) returns (x: int) ensures n % 2 == 0 => /* Omitted. */ ensures n % 2 == 1 ==> /* Omitted. */ /* The body of the method has also been omitted. */ The method also has a tester. Both the method and the tester verify. There are many ways to express the postcondition for DivideBy2. Which is not correct? (a) O (b) O (c) O (d) O (e) O ensures if n % 2 != 0 then n == 2*x + 1 else n == 2*X ensures n == if n % 2 ensures if n % 2 == ensures n % 2 ====> n == 2*x && n % 2 == 1 ==> n == 2*x + 1 == 0 then 2*x else 2*x + 1 0 then n == 2*x + n * (n % 2) else n == 2*x*(n % 2) + 1 ensures n == 2*x +n % 2 Consider the following method that divides an integer by 2: method DivideBy2(n: int) returns (x: int) ensures n % 2 == 0 => /* Omitted. */ ensures n % 2 == 1 ==> /* Omitted. */ /* The body of the method has also been omitted. */ The method also has a tester. Both the method and the tester verify. There are many ways to express the postcondition for DivideBy2. Which is not correct? (a) O (b) O (c) O (d) O (e) O ensures if n % 2 != 0 then n == 2*x + 1 else n == 2*X ensures n == if n % 2 ensures if n % 2 == ensures n % 2 ====> n == 2*x && n % 2 == 1 ==> n == 2*x + 1 == 0 then 2*x else 2*x + 1 0 then n == 2*x + n * (n % 2) else n == 2*x*(n % 2) + 1 ensures n == 2*x +n % 2
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Related Book For
Java An Introduction To Problem Solving And Programming
ISBN: 9780134462035
8th Edition
Authors: Walter Savitch
Posted Date:
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