Question: continue the explanation and start from Step 4: Combine the results [ int sin(6x) sin(2x) , dx = frac{1}{2} left( frac{1}{4} sin(4x) - frac{1}{8} sin(8x)

continue the explanation and start from Step 4: Combine the results [ \int \sin(6x) \sin(2x) , dx = \frac{1}{2} \left( \frac{1}{4} \sin(4x) - \frac{1}{8} \sin(8x) ight) + C ] [ = \frac{1}{8} \sin(4x) - \frac{1}{16} \sin(8x) + C ]

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