Question: Convert pseudocode to ARM: if ( ( X 2 ! = 2 ! = X 3 ) 3 ) X 4 = 4 = X

Convert pseudocode to ARM:
if ((X2!=2!= X3)3)
X4=4= X4+4+ X44;
ADD
X44
,,
X44
,,
X44
ADD
X44
,,
X44
,,
X44
ADD
X44
,,
X44
,,
X44
L11:

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