Could you help me with this problem please ? I did it but it is look like it is false, I attached the feedback and how I did.

20. Consider the function f(x) = x for x ER and -2 1 f(x) = 1. Use the method shown in Example 3.7.5.Approach to Solution Our goal is to first find a positive number & We have: e>0 8 = some positive number 00 Approach to Solution 4 |x3 - 1| = |(x - 1)(x2 + x + 1)| = (x2 + x + 1)|x - 1| |x - 1| 0 then & is a positive number. |x3 - 1| = |(x - 1)(x2 + x + 1)| = (x2 + x+ 1)|x - 1| 0 Let delta = min{1, epsilon/7} Let x be a real number such that -2 |x-1]-101 (x"2 + x + 1)(delta) [f(x) - 1|