Question: Determine whether the series infty 3 2 n 2 2 n 7 n = 1 converges or diverges. Solution For large n the dominant

Determine whether the series \infty 32n22n 7 n =1 converges or diverges. Solution For large n the dominant term in the denominator is 2n2, so we compare the given series with the series 3(2n2). Observe that 32n22n 732n2 because the left side has a bigger denominator. (In the notation of the Comparison Test, an is the left side and bn is the right side.) We know that \infty 32n2 n =1=\infty 1 n2, n =1 which is convergent because it's a constant times a p-series with p =>1. Therefore \infty 32n22n 7 n =1 is by the Comparison Test.

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