Question: Dynamic models - Stirred tank heating process ( Constant holdup ) Assumptions: Perfect mixing Liquid holdup is constant ) = ( w p and C

Dynamic models - Stirred tank heating process (Constant holdup)
Assumptions:
Perfect mixing
Liquid holdup is constant )=(w
p and C are constant
Heat losses are negligible
NF=4-1
=3.
Energy balance:
dUintdt=VCdTdt,=>NfWhichcomindvalesand=3
-(what(H))=w[C(Ti-Tret)]-w[C(T-Tref)]
Parameter: V,,C
Which com take amb, Pariables: T,T,w,w,Q
Nv=4,NE=1;Nf=Nv-NE=4-1=3
eutput: Y, Disturbance:
Manipulated: Q(m).
detail out how we arrive the mass and energy balance equation given in the figure
 Dynamic models - Stirred tank heating process (Constant holdup) Assumptions: Perfect

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemical Engineering Questions!