Equilibrium constant Solution 1 2 3 4 5 Absorbance 0.07 0.20 0.31 0.42 0.50 Initial molarity...

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Equilibrium constant Solution 1 2 3 4 5 Absorbance 0.07 0.20 0.31 0.42 0.50 Initial molarity (= mol/L) Equilibrium Concentrations Fe3+ HSCN FeSCN²+ Fe³+ HSCN FeSCN²+ H+ Average K. = Kc Complete the table above using ICE diagrams to calculate K values. You need only show work for the calculation of K for unknown 1. Equilibrium constant Solution 1 2 3 4 5 Absorbance 0.07 0.20 0.31 0.42 0.50 Initial molarity (= mol/L) Equilibrium Concentrations Fe3+ HSCN FeSCN²+ Fe³+ HSCN FeSCN²+ H+ Average K. = Kc Complete the table above using ICE diagrams to calculate K values. You need only show work for the calculation of K for unknown 1.

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Solution Absorbance hitial molarity molL HSCN 000020 1 2 3 007 Average 620 031 642 050 Average Ko F3 ... View the full answer