Question: Equilibrium-to-Acids and Bases ke = [Hz or ] [ chos For the reaction: HCHO,(aq) + H20(1) - H20 (aq) + CHO (1) 1) Write out

 Equilibrium-to-Acids and Bases ke = [Hz or ] [ chos For
the reaction: HCHO,(aq) + H20(1) - H20" (aq) + CHO (1) 1)

Equilibrium-to-Acids and Bases ke = [Hz or ] [ chos For the reaction: HCHO,(aq) + H20(1) - H20" (aq) + CHO (1) 1) Write out the expression for the equilibrium constant ] [HC Ho] 2) At equilibrium, IH,0") = 4.24 x 10-7. (HCHO:] = 0.96M, and (CHO) = 4.24 x 10-'M. Find K. ket 4.24x10 Xorivaid 0.76m = 1.8727X10-S 3) Computeko boet on=0 kp=ke = 1.382280 4) An additional 0.00100M H,Ois added to the solution A. Based on LeChatelier's Principle, how will this affect the equilibrium? This will increuse the volume of the recent Kp = Ke Crijon pakelRT) B. Determine 0. Does this match your prediction from part A? C. Set up an IC table based on and determine the new equilibrium concentrations HO HO HO CHO Jarhal chege Epaille D. The volume of the system is decreased in half. Is the system still at equilibrium? If not, compute Q and bring the system back to equilibrium

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