Question: Example: 100 kg box is sitting on a floor. The coefficient of static friction between the box and the floor is 0.40. What is the

Example: 100 kg box is sitting on a floor. The coefficient of static friction between the box and the floor is 0.40. What is the force (applied at 30 degree above the horizontal as shown) required to get the box to start moving? x - direction y - direction F F g F = ma F. = ma A NETx X NETy y 30 F Ax - F. = ma F. - F - F = ma g F cos(30) - F. = 0 F =F +F N g Ay A F = UF / cos(30) F = mg + F sin(30) F F f F = umg (0.4)(100) (9.8) N A cos30-usin30 = 589N ORE VIDEOS cos30-(0.4)sin30

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