Explain what it means to say that lim f(x) = 8 and x-37 lim f(x) = 5. x-3+ O As x approaches 3 from the right, f(x) approaches 8. As x approaches 3 from the left, f(x) approaches 5. O As x approaches 3 from the left, f(x) approaches 8. As x approaches 3 from the right, f(x) approaches 5. O As x approaches 3, f(x) approaches 5, but f(3) = 8. O As x approaches 3, f(x) approaches 8, but f(3) = 5. In this situation is it possible that lim f(x) exists? Explain. X-3 Yes, f(x) could have a hole at (3, 8) and be defined such that f(3) = 5. O Yes, f(x) could have a hole at (3, 5) and be defined such that f(3) = 8. Yes, if f(x) has a vertical asymptote at x = 3, it can be defined such that lim f(x) = 8, lim f(x) = 5, and lim f(x) exists. No, lim f(x) cannot exist if lim f(x) = lim f(x). X-3 x-3 x-3+ X-3