Question #2

Explain what it means to say that lim f(x) = 7 and lim f(x) = 5. X - 6- x - 6 As x approaches 6 from the right, f(x) approaches 7. As x approaches 6 from the left, f(x) approaches 5. O As x approaches 6, f(x) approaches 7, but f(6) = 5. As x approaches 6, f(x) approaches 5, but f(6) = 7. As x approaches 6 from the left, f(x) approaches 7. As x approaches 6 from the right, f(x) approaches 5. In this situation is it possible that lim f(x) exists? Explain. x - 6 Yes, f(x) could have a hole at (6, 7) and be defined such that f(6) = 5. O Yes, f(x) could have a hole at (6, 5) and be defined such that f(6) = 7. Yes, if f(x) has a vertical asymptote at x = 6, it can be defined such that lim f(x) = 7, lim f(x) = 5, and lim f(x) exists. x - 6 - x - 6+ x - 6 O No, lim f(x) cannot exist if lim f(x) * lim f(x). X-6 X- 6+