Explain what it means to say that lim f(x) = 1 and lim f(x) = 9. x - 3 x - 3+ O As x approaches 3 from the right, f(x) approaches 1. As x approaches 3 from the left, f(x) approaches 9. O As x approaches 3, f(x) approaches 9, but f(3) = 1. As x approaches 3 from the left, f(x) approaches 1. As x approaches 3 from the right, f(x) approaches 9. O As x approaches 3, f(x) approaches 1, but f(3) = 9. In this situation is it possible that lim f(x) exists? Explain. x - 3 O Yes, f(x) could have a hole at (3, 1) and be defined such that f(3) = 9. O Yes, f(x) could have a hole at (3, 9) and be defined such that f(3) = 1. Yes, if f(x) has a vertical asymptote at x = 3, it can be defined such that lim f(x) = 1, lim f(x) = 9, and lim f(x) exists. x- 3- x - 3+ x - 3 No, lim f(x) cannot exist if lim f(x) # lim f(x). X - 3 x - 3 X - 3+ his