I need solve this question

Explain what it means to say that lim f(x) = 9 and lim f(x) = 1. X - 6 x - 6+ As x approaches 6, f(x) approaches 9, but f(6) = 1. As x approaches 6 from the right, f(x) approaches 9. As x approaches 6 from the left, f(x) approaches 1. As x approaches 6 from the left, f(x) approaches 9. As x approaches 6 from the right, f(x) approaches 1. As x approaches 6, f(x) approaches 1, but f(6) = 9. In this situation is it possible that lim f(x) exists? Explain. X - 6 Yes, f(x) could have a hole at (6, 9) and be defined such that f(6) = 1. C Yes, f(x) could have a hole at (6, 1) and be defined such that f(6) = 9. Yes, if f(x) has a vertical asymptote at x = 6, it can be defined such that lim f(x) = 9, lim f(x) = 1, and lim f(x) exists. X - 6 X -+ 6+ X - 6 No, lim f(x) cannot exist if lim f(x) * lim f(x). X - 6 X - 6 X -+ 6+