(f) Revisit Example 2-6. If the term CA00XrAdX is 2 seconds for 80% conversion, how much fluid (m3/min) can you process in a 3m3 reactor? Example 2-6 Reactor Space Times and Space Velocities Calculate the space time, , and space velocities for the reactor in Examples 2-1 and 2-3 for an entering volumetric flow rate of 2dm3/s. Solution The entering volumetric flow rate is 2dm3/s(0.002m3/s). From Example 2-1, the CSTR volume was 6.4m3 and the corresponding space time, , and space velocity, SV are =v0V=0.002m3/s6.4m3=3200s=0.89h It takes 0.89 hours to put 6.4m3 into the reactor. SV=1=0.89h1=1.125h1 From Example 2-3, the PFR volume was 2.165m3, and the corresponding space time and space velocity are =v0V=0.002m3/s2.165m3=1083s=0.30hSV=1=0.30h1=3.3h1 Analysis: This example gives an important industrial concept. These space times are the times for each of the reactors to take the volume of fluid equivalent to one reactor volume and put it into the reactor