Question: FBD & Equilibrium equations Using the FBDs , of cut sections between A&B and between C&D , shown ? ? M x = 0 =

FBD & Equilibrium equations
Using the FBDs, of cut sections between A&B and between C&D, shown
??Mx=0=>TAB=T
??Mx=0=>TCD=T
Design w.r.t max. shear stress in AB
ABmaxallst=>TAB0.85(in)(2(0.85)4)(in4)14(kipin2)=>TAB13.503(kip*in)=>T13.503(kip*in)
Design w.r.t max. shear stress inCD
Design w.r.t max. shear stress in CD
CDmaxallbr=>TCD1.4(in)(2((1.4)4-(1.15)4))(in4)7(kipin2)=>TCD16.432(kip*in)=>T16.432(kip*in)
The allowable torque Tis(kip.in) and isa
The allowable torque T is (
kip.in) and is a
FBD & Equilibrium equations Using the FBDs , of

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