Follow the steps below for the given function.

$x^3-6x^2-xy=7$

Solve the equation for $y.$

$y=$

Differentiate this equation with respect $tox.$

$y^{\text{'}}=x$ and $y.x^3-6x^2-xy=7$

$-xy=7-x^3+6x^2$

$\frac{d}{dx}(-xy)=\frac{d}{dx}(7)-\frac{d}{dx}(x^3)+\frac{d}{dx}(6x^2)$

$-x\frac{d}{dx}(y)-y\frac{d}{dx}(x)=0-3x^2+$

$-x\frac{dy}{dx}=-3x^2+$

$\frac{dy}{dx}=$