Question: For a protein with two ligand binding sites, the binding polynomial has the general form: Q=[P](1+2k 1 [L]+k 1 k 2 [L] 2 ) where

For a protein with two ligand binding sites, the binding polynomial has the general form: Q=[P](1+2k1[L]+k1k2[L]2) where [P] is the unbound protein concentration and [L] is the free ligand concentration. The equilibrium constants are defined as: k1=[PL]/[P][L] and k2=[PL2]/[PL][L] a.) Assume k1=k2=k=10 and [L]=0.15. Calculate the fraction of sites bound fB. (fB does not equal 0.84).

b.) Consider a model where k1=For a protein with two ligand binding sites, the binding polynomial hask and k2=k . If k = 10 and [L]=0.15 calculate the binding fraction. the general form: Q=[P](1+2k1[L]+k1k2[L]2) where [P] is the unbound protein concentration and=0.1

c.) Assume k1=k2=k=10 and [L]=2. Calculate the fraction of sites bound fB.

d.) Consider a model where k1=[L] is the free ligand concentration. The equilibrium constants are defined as:k and k2=k . If k = 10 and [L]=2 calculate the binding fraction. k1=[PL]/[P][L] and k2=[PL2]/[PL][L] a.) Assume k1=k2=k=10 and [L]=0.15. Calculate the fraction of=0.1

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemistry Questions!