Question: For the function f(3::,y) : 43:2 | 3:33; 5y2 4m | y | 3, find a unit tangent vector to the level curve at the


For the function f(3::,y) : 43:2 | 3:33; 5y2 4m | y | 3, find a unit tangent vector to the level curve at the point (1, 3) that has a positive a: component. Round your numbers to four decimal places
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