Question: For the function: x +3 f ( x ) = -x2 - 6x - 4 f' (x) = 2(x3 + 9x2 + 12x + 12)

For the function: x +3 f ( x ) = -x2
- 6x - 4 f' (x) = 2(x3 + 9x2 + 12x

For the function: x +3 f ( x ) = -x2 - 6x - 4 f' (x) = 2(x3 + 9x2 + 12x + 12) (x2 - 4) (x2 - 4)2 f"(x) = (x2 - 4)3

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