For the reaction:

$A(g)+B(g)AB(g)$

the rate is $0\mathrm{.}27\frac{\text{m}\text{o}\text{l}}{L*s}$ when $[A{]}_0=[B{]}_0=1\mathrm{.}0\frac{\text{m}\text{o}\text{l}}{L}.$ If the reaction is first$-$order in $B$ and second$-$order in $A,$ what is the rate when $[A{]}_0=2\mathrm{.}3\frac{\text{m}\text{o}\text{l}}{L}$ and $[B{]}_0=3\mathrm{.}7\frac{\text{m}\text{o}\text{l}}{L}?$ Be sure your answer has the correct number of significant figures.

$\frac{\text{m}\text{o}\text{l}}{L*s}$

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