Question: For the reaction: F e 2 O 3 ( s ) + 2 A l ( s ) 2 F e ( l ) +

For the reaction:
Fe2O3(s)+2Al(s)2Fe(l)+Al2O3(s)
What mass of aluminum must be used to produce 25.0g of iron?
Fe=56gmol,Al=27gmol,
12.1g
24.2g
46.3g
6.21g
For the reaction: Fe2O3(s)+2Al(s)2Fe(l)+Al2O3(s) What mass of aluminum must be used

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