Form the Karnaugh map from the truth table and hence simplify

the following logic functions $($output $=$ F$).$

$($a$)(30$ points$)$

A B C F

$0000$

$0011$

$0100$

$0110$

$1001$

$1011$

$1101$

$1111$

$($b$)(30$ points$)$

A B C F

$0001$

$0010$

$0101$

$0110$

$1001$

$1011$

$1101$

$111$ X

$($c$)(40$ points$)$

A B C D F

$00001$

$00011$

$00100$

$00110$

$01001$

$01011$

$0110$ X

$01110$

$10001$

$10011$

$1010$ X

$10111$

$11001$

$1101$ X

$11101$

$1111$ X