Question: Forward Kinematics 1 . The manipulator arm shown below has two revolute joints, with ( mathrm { L } _ { 1 }

Forward Kinematics
1. The manipulator arm shown below has two revolute joints, with \(\mathrm{L}_{1}=0.3\mathrm{~m},\mathrm{~L}_{2}=0.2\mathrm{~m}.\mathrm{L}_{2}\) is the distance from the \(\mathrm{L}_{2}\) axis of rotation to the center point of the tip of the tool (end effector)
a. Copy the manipulator diagram to your paper. Label the base coordinate frame, coincident with the first axis of rotation.
b. Label the coordinate frames for \(\mathrm{L}_{1},\mathrm{~L}_{2}\) and the tool frames, according to D-H convention (from class lecture.
c. Label the angles for rotation, measured with CCW rotation.
d. Find
e. Find
f. Find
g. Find
Forward kinematics verification
2. Compute for the following cases (use MATLAB or hand calculate) and sketch each configuration.
Forward Kinematics 1 . The manipulator arm shown

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