Machine (x) (indoor) Sound level (Lp1) = 95dBA Ta = 30c Tg = 89F Tnwb = 29c Time (T1) = 120 minutes g CO = 0.003m- 3 m Machine (Z) (indoor) Sound level (Lp3) = 90dBA, Time (T3) = 2 hours WBGT = 29.2C CO = 12ppm Machine (F) (outdoor) WBGT = 28.9c Sound level (Lp4)= 85dBA Time (T4) = 120 minutes g CO2 = 15m- m 3 From figure calculate: (1) Lp total (noise) by logarithmic method and by traditional method. (2) Calculate WBGT-TWA for worker work in all machines (x, y, z and f). (3) If machine Y covered lead to decrease Tnwb two degrees calculate WBGT in this situation. (4) Effective daily dose (noise) for worker work in all machines (x, y, z and f) (Action level 90 dBA). (5) TWA for co for worker work in all machines (x, y, z and f). Machine (X) (indoor) Sound level (Lp1)-95dBA Ta=30c Tg-89F Tnwb=29c Time (T1)=120 minutes Coz = 0.003 mg/m* Machine (Y) (outdoor) Sound level (Lp2)=90dBA Time (T2)=2hours Ta-87.8f Tg-32c Tnwb=29C Co = 0.0 ppm Machine (F) (outdoor) WBGT=28.9c Sound level (Lp4)=85dBA Time (T4)=120 minutes Coi = 15 mg/m Machine (Z) (indoor) Sound level (Lp3)=90dBA Time (T3)=2hours WBGT= 29.2 C CO = 12 ppm