Question: Given: 2e + Cl2 2Cl ; E=+1.36 volts Cl2 + H2O HOC l+ H+ + Cl ; Kh=3.810^4 and Kw=10^14 calculate E for the reaction

Given: 2e + Cl2 2Cl ; E=+1.36 volts

Cl2 + H2O HOC l+ H+ + Cl ; Kh=3.810^4 and Kw=10^14

calculate E for the reaction 2e + HOCl Cl + OH

NOTE: The first equation given involves Cl2(g); the second equation involves Cl2(aq). You need to use the Henrys Law constant from equation Cl2(g)---> Cl2(aq) Kh= 6.2*10^-2

Final answer should be E= +1.05 volt

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