Question: Given: 2e + Cl2 2Cl; E=+1.36 volts Cl2 + H2O HOC l+ H+ + Cl; Kh=3.810^4 and Kw=10^14 calculate E for the reaction 2e +

Given: 2e + Cl2 2Cl; E=+1.36 volts

Cl2 + H2O HOC l+ H+ + Cl; Kh=3.810^4 and Kw=10^14

calculate E for the reaction 2e + HOCl Cl + OH

NOTE: You need to use the Henrys Law constant from equation Cl2(g)---> Cl2(aq) Kh= 6.2*10^-2

Final answer E= +1.05 volt

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