Given a positive integer $n,$ the following rules will always create a sequence that ends

with $1,$ called the hailstone sequence:

If $n$ is even, divide it by two

If $n$ is odd, multiply it by $3$ and add $1($i$.$e$.3n+1)$

Continue until $n$ is $1$

Write a program that reads an integer as input and prints the hailstone sequence

starting with the integer entered. Format the output so that five integers, each

separated by a tab character $(\frac{?}{t}),$ are printed per line. End the output with a tab

character.

The output format can be achieved as follows:

cout $"\backslash$t$"$;

$Ex$: $If$ the input $is$:

$25$

the output $is$: