Question: Given the HLL code: if (numi >= 60) numl++; When the compiler associates variable num1 with register $16, the assembly code equivalent (with the first

Given the HLL code: if (numi >= 60) numl++; When the

Given the HLL code: if (numi >= 60) numl++; When the compiler associates variable num1 with register $16, the assembly code equivalent (with the first line missing) is: missing: bne $8, $0, next addi $16, $16, 1 next: Using only the subset of MIPS instructions presented in the Content, what is the missing line of MIPS assembly code? Be sure to include a space after each comma in your

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