Help me solve this | All parts showing Data collected on the yearly registrations for a Six Sigma seminar at the Quality College are shown in the following table: Year 1 2 3 7 8 4 5 6 9 10 11 4.00 4.00 10.00 9.00 6.00 9.00 12.00 16.00 17.00 Registrations (000) 3.00 5.00 Using exponential smoothing with a = 0.40 and a forecast for year 1 of 6.00, provide the forecast from periods 2 through 12 (round your response to one decimal place). F F-1 + (A-1-Ft-1), where x = smoothing constant between 0 and 1 is the relationship to be used for developing the forecast. For developing the Year 2 Forecast, the values to be used in the above relationship are 6.00 +0.40(3.00 - 6.00). Forecasted registrations for years 2 through 12 using exponential smoothing, with a smoothing constant (x) of 0.40 and a starting forecast of 6.00 for year 1, are: Year Forecast (000) 1 6.00 2 3 4 4.8 4.9 4.5 6 5 4.3 6.6 MAD = 7 7.6 8 7.0 Actual - Forecast n 9 7.8 10 11 9.5 12.1 12 14.1 The value of MAD is computed by taking the sum of the absolute values of the individual forecast errors (deviations) and dividing by the number of periods of data (n): X The absolute deviation based on the forecast developed for each period using the exponential smoothing method (with a smoothing constant (x) = 0.40 and a starting forecast of F = 6.00) adds to 31.90 (round your response to two decimal places). Mean absolute deviation based on the forecast developed using the exponential smoothing method (with a smoothing constant (x) = 0.40 and a starting forecast of F = 6.00) is 2.9 registrations (round your response to two decimal places)