Question: How do we find the specific internal energy(h) in the steam tables according to this solution? A heat exchanger, shown in the figure, is used

How do we find the specific internal energy(h) in the steam

How do we find the specific internal energy(h) in the steam tables according to this solution?

A heat exchanger, shown in the figure, is used to cool an air flow from 700 to 400K, with both states at 1MPa. The coolant is a water flow at 20C and 100kPa. If the water leaves as saturated vapor at a mass flow rate of 0.5kg/s, find the mass flow rate of air. For air, the specific heat ratio under constant pressure is 1004J/kgK SOLUTION From saturated water table B.1.1. at 100kPa and 20C h1=hf=83.94kJ/kgh4=hg=2538kJ/kg For the control volume about the heat exchanger mah1+mwh3=mah1+mwh3ma=cp(T1T2)mw(h3h4)=(1.004kJ/kgK)(700K400K)(0.5kg/s)(2538kJ/kg83.94kJ/kg)=

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