how is rhe MSE found for this question given the MAD is .150?

Problem 4.14 Question Help Following are two weekly forecasts made by two different methods for the number of gallons of gasoline, in thousands demanded at a local gasoline station Also shown are actual demand levels, in thousands of gallons Week 1 2 3 4 Forecast Method 1 0.95 1 08 0.92 120 Actual Demand 0.72 098 0.96 0.97 Week 1 2 3 4 Forecast Method 2 0.80 1.19 0.92 Actual Demand 072 098 096 0.97 1.11 The MAD for Method 1 = 0.150 thousand gallons (Yound your response to three decimal placea) The mean squared error (MSE) for Method 1 -thousand gallons fround your response to three decimal places Following are two weekly forecasts made by two different methods for the number of gatom of gasoline, in thousands demanded at a bal gasoline station. Also shown are actual demand levels in thousands of gatos Web 1 2 3 4 Forecast Method 1 0.95 18 0.92 120 Actual Demand 0.72 0.98 0.96 0.97 Week 1 2 3 1 Forecast Method 2 0.80 119 0.92 1.11 Actual Demand 072 0.98 0.95 The MAD for Method 1 - 0 150 thousand golons fround your response to the decimale) The moan squared ener (MSC) for Method - thousand gallons (round your aponse to the decom placea)