I didn't know how to solve this problem using loops (on MATLAB)

A weight W is supported by two cables anchored a distance D apart BC The cable length LAB is given, but the length LBc is to be selected. Each cable can support a maximum tension force equal to W. For the weight to remain stationary, the total horizontal force and total vertical force must each be zero. This principle gives the equations TAB sine+ TBC sin -w we can solve these equations for the tension forces TAB and TBC if we know the angles and . From the law of cosines 2DLAB From the law of sines sin BC = sin-1 For the given values D 6 ft, LAB 3 ft, and W 2000 lb, use a loop in MATLAB to find LBCmin, the shortest length LBc we can use without TAB or TBc exceeding 2000 lb. Note that the largest LBc can be 6.7 ft (which corresponds to = 90). Plot the tension forces TAB and TBC on the same graph versus Lec for Lecmin S Lec S 6.7