Question: I need help Given the function 9(m) = 6:133 + 18:1:2 1443:, find the first derivative, 9'03). 9'0) = :1 Notice that g'(a:) = 0
I need help

Given the function 9(m) = 6:133 + 18:1:2 1443:, find the first derivative, 9'03). 9'0\") = :1 Notice that g'(a:) = 0 when :1: = 2, that is, g'(2) = 0. Now, we want to know whether there is a local minimum or local maximum at :1: = 2, so we will use the second derivative test. Find the second derivative, 9' '.(a:) 9' W = :1 Evaluate g' '.(2) 9'12) =:] Based on the sign of this number, does this mean the graph of 9(3) is concave up or concave down at :1: = 2? [Answer either up or down -- watch your spelling!!] At a: = 2 the graph of g(a:) is concave :] Based on the concavity of g(a:) at a: = 2, does this mean that there is a local minimum or local maximum at :1: = 2? [Answer either minimum or maximum -- watch your spelling!!] At a: = 2 there is a local :]
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