Question: ID Slope Normal Time Normal Cost, $ Crash Time Crash Cost, $ A 25 8 150 6 200 B 150 4 200 3 350 C
| ID | Slope | Normal Time | Normal Cost, $ | Crash Time | Crash Cost, $ |
|---|---|---|---|---|---|
| A | 25 | 8 | 150 | 6 | 200 |
| B | 150 | 4 | 200 | 3 | 350 |
| C | 100 | 8 | 150 | 7 | 250 |
| D | 100 | 7 | 350 | 4 | 650 |
| E | 75 | 9 | 250 | 7 | 400 |
| F | 150 | 7 | 500 | 6 | 650 |
| G | 200 | 4 | 400 | 3 | 600 |
| H | 50 | 8 | 400 | 6 | 500 |
| I | 175 | 7 | 100 | 5 | 450 |
Given the above table of Software Developing Project, what is the total normal cost of the project?
Answer:
Consider your calculations from the previous question.
If the critical path is B-D-E-H-I, which activity should be crashed first.
Select one:
Activity A
Activity B
Activity C
Activity D
Activity E
Activity F
Activity G
Activity H
Activity I
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Question text
If you were asked to reduce the project by three days, what activities would you crash?
* Iteration 1: Activity AnswerABCDEFGHI
* Iteration 2: Activity AnswerABCDEFGHI
* Iteration 3: Activity AnswerABCDEFGHI
Question text
What is the extra amount you will have to pay for crashing the project by three days?
Answer:
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