Question: If we apply Rolle's Theorem to the function f(x) = 2x2 - 12x - 1 on the interval [1, 5], how many values of c

![- 12x - 1 on the interval [1, 5], how many values](https://s3.amazonaws.com/si.experts.images/answers/2024/06/667d2301545bb_993667d2301377eb.jpg)
If we apply Rolle's Theorem to the function f(x) = 2x2 - 12x - 1 on the interval [1, 5], how many values of c exist such that f' (c) = 0? What is the value of c? If we try to apply Rolle's Thorem to the function f(a) = 2x2 - 12x - 1 on the interval [ - 2, 12], which of the following conditions is not met? Of(a) # f(b) O continuty on [ - 2, 12] O differentiability on [ - 2, 12]
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