Using the ANOVA table listed below, what should our conclusion be? ANOVA Source of Vartation Between...

   

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Using the ANOVA table listed below, what should our conclusion be? ANOVA Source of Vartation Between Groups Within Groups Total S.S 3.631344 1.103017 4.734361 MS 2 1.815672 15 0.073534 17 F P-value 24.69145 0.0000179548 3.682320344 F crit our means are not significantly different from one another. We Since Ferit = 3.68, we fail to reject the null hypothesi must now complete Tukey's HSD to determine if there are mean differences between specific group pairs. Since F= 24.69, we reject the null hypothesis; our means are not significantly different from one another so we do not need to complete Tukey's HSD. Since p < .05, we reject the null hypothesis; our means are significantly different from one another. We must now complete Tukey's HSD to determine which means differ significantly from one another. Since p>.05, we fail to reject the null hypothesis; our means are significantly different from one another. We must now complete Tukey's HSD to determine which means differ significantly from one another. Using the ANOVA table listed below, what should our conclusion be? ANOVA Source of Vartation Between Groups Within Groups Total S.S 3.631344 1.103017 4.734361 MS 2 1.815672 15 0.073534 17 F P-value 24.69145 0.0000179548 3.682320344 F crit our means are not significantly different from one another. We Since Ferit = 3.68, we fail to reject the null hypothesi must now complete Tukey's HSD to determine if there are mean differences between specific group pairs. Since F= 24.69, we reject the null hypothesis; our means are not significantly different from one another so we do not need to complete Tukey's HSD. Since p < .05, we reject the null hypothesis; our means are significantly different from one another. We must now complete Tukey's HSD to determine which means differ significantly from one another. Since p>.05, we fail to reject the null hypothesis; our means are significantly different from one another. We must now complete Tukey's HSD to determine which means differ significantly from one another.

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Since pvalue 0000017 005 we reject the null ... View the full answer