In Python

A. Define a function called has_letter ( that takes a string, returns True if the string has at least one alphabetic letterl, and returns False otherwise. For example, has_letter ("ABC", has_letter ("2x4", and has_letter("T 2/6") should all return True, but has-letter ( "65, 537" ) and has.-letter ( " $@ ! " ) should return False. Your function should use a for loop to do this calculation [1 Hint: the Python string method isalpha can be used to determine if a string consists of only alphabetic letters. For example, "a".isalpha() and " ?????". isalpha ( ) return True, while " ! " . is alpha ( ) and "X&Y", is alpha ( ) return False. (Using.isalpha() is better than just checking a letter against the 26 uppercase and 26 lowercase English letters because there are many non-English letters out there.) You can read more about .isalpha() in the the Official Python Documentation, if you like