Question: Lead ion react with phoshate ion to form the sparingly soluble Pb3(PO4)2 3Pb(NO3)2 + 2Na3PO4 Pb3(PO4)2 + 6NaNO3 What weight of Pb3(PO4)2 will form
Lead ion react with phoshate ion to form the sparingly soluble Pb3(PO4)2 3Pb(NO3)2 + 2Na3PO4 Pb3(PO4)2 + 6NaNO3
What weight of Pb3(PO4)2 will form when 2.50 L of 0.285M Na3PO4 are mixed with 0.600 L of 0.178M Pb(NO3)2?
Step by Step Solution
3.40 Rating (147 Votes )
There are 3 Steps involved in it
Moles of Na3PO4 02852507125 moles Moles of PbNO32 0178060001068 moles But according t... View full answer
Get step-by-step solutions from verified subject matter experts
