Question: Lead ion react with phoshate ion to form the sparingly soluble Pb3(PO4)2 3Pb(NO3)2 + 2Na3PO4 Pb3(PO4)2 + 6NaNO3 What weight of Pb3(PO4)2 will form

 Lead ion react with phoshate ion to form the sparingly soluble Pb3(PO4)2  3Pb(NO3)2 + 2Na3PO4  Pb3(PO4)2 + 6NaNO3

What weight of Pb3(PO4)2 will form when 2.50 L of 0.285M Na3PO4 are mixed with 0.600 L of 0.178M Pb(NO3)2?

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Moles of Na3PO4 02852507125 moles Moles of PbNO32 0178060001068 moles But according t... View full answer

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