Question: Need help with only question 4, need help with the MATLAB code. Q1 is there for reference for Q4. 4. Use MATLAB and plot the

Need help with only question 4, need help with the MATLAB code. Q1 is there for reference for Q4.

Need help with only question 4, need help with the MATLAB code.

Q1 is there for reference for Q4. 4. Use MATLAB and plot

4. Use MATLAB and plot the following quantities for the motor in Q1 as slip varies from 0% to 10% (25 points: Each part 5 points) (b) P... (c) Po (d) Efficiency (e) At what slip does Pout equal the rated power of the machine? You can use the curve in Part (c) to read this speed and its corresponding slip value. 1. A 140-V 50-Hz two-pole Y-connected induction motor is rated at 75 kW. The equivalent cir- cuit parameters are R = 0.075 , X; = 0.17 2, R = 0.065 2, X, = 0.17 12, XM = 7.2 A, Priction Windoge = 1 kW, Porniscellaneous = 150 W, and Pare = 1.1 kW. These three categories of losses are lumped together and called rotational losses. Protatiotal = Pfriction&Windloge + Pirmiscellaneous + Pare The total rotational losses (Protatioma) of a motor are often considered to be constant with changing speed. For a slip of 0.04, find: (30 points: Each part 3 points). (a) The line current I (b) The stator power factor (e) The rotor power factor () The stator copper losses PC (e) The air-gap power PAG (f) The power converted from electrical to mechanical form Poom (8) The induced torque Tind (h) The load torque Toad (i) The overall machine efficiency 6) The motor speed in revolutions per minute and radians per second 4. Use MATLAB and plot the following quantities for the motor in Q1 as slip varies from 0% to 10% (25 points: Each part 5 points) (b) P... (c) Po (d) Efficiency (e) At what slip does Pout equal the rated power of the machine? You can use the curve in Part (c) to read this speed and its corresponding slip value. 1. A 140-V 50-Hz two-pole Y-connected induction motor is rated at 75 kW. The equivalent cir- cuit parameters are R = 0.075 , X; = 0.17 2, R = 0.065 2, X, = 0.17 12, XM = 7.2 A, Priction Windoge = 1 kW, Porniscellaneous = 150 W, and Pare = 1.1 kW. These three categories of losses are lumped together and called rotational losses. Protatiotal = Pfriction&Windloge + Pirmiscellaneous + Pare The total rotational losses (Protatioma) of a motor are often considered to be constant with changing speed. For a slip of 0.04, find: (30 points: Each part 3 points). (a) The line current I (b) The stator power factor (e) The rotor power factor () The stator copper losses PC (e) The air-gap power PAG (f) The power converted from electrical to mechanical form Poom (8) The induced torque Tind (h) The load torque Toad (i) The overall machine efficiency 6) The motor speed in revolutions per minute and radians per second

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