Now that the order for both reactants is known, the rate constant, k$,$ can be determined.

Each of the four trials can be used to calculate $k$ and then the four results can be averaged.

We will use Trial $4$ to determine the rate constant in this example.

What is the value of the rate constant?

$\backslash$table$[[,[A],mo\frac{l}{L},[B],mo\frac{l}{L},$rate, mol$/($L$-$min$)],[$Trial $1,0\mathrm{.}863,0\mathrm{.}914,0\mathrm{.}240],[$Trial $2,1\mathrm{.}73,0\mathrm{.}914,0\mathrm{.}480],[$Trial $3,0\mathrm{.}863,1\mathrm{.}83,0\mathrm{.}960],[$Trial $4,0\mathrm{.}885,0\mathrm{.}488,0\mathrm{.}0702]]$

Rate $=k[A{]}^1[B{]}^2$

L$/$mol$-$min

of $5$