Question: Parallel Plate Capacitor Design and Dielectric Properties Analysis A parallel plate capacitor is designed with a dielectric material of relative permittivity ( r ) equal

Parallel Plate Capacitor Design and Dielectric Properties Analysis
A parallel plate capacitor is designed with a dielectric material of relative permittivity (r) equal to 6.0. The following conditions are provided. Based on these, answer the questions below.
Given:
Plate area: A=5.010-4m2
Distance between plates: d=0.002m
Applied voltage: V=10 V
Permittivity of free space: 0=8.8510-12Fm
Questions:
a. Calculate the capacitance C of the capacitor.
b. Determine the charge Q stored on each plate.
c. Compute the dielectric displacement D.
d. Calculate the polarization P of the dielectric material.
e. If the dielectric strength Ebd=5106Vm, calculate the maximum voltage the capacitor can withstand without breakdown.
f. if the dielectric material that has a relative permittivity (r) dependent on frequency as below.
Frequency-dependent relative permittivity (r) :
1Hz:r=6.0
106Hz:r=4.5
1012Hz:r=3.8
1016Hz:r=3.5
Calculate C and Q at each frequency.
g. Explain how the frequency of the applied field affects each polarization mechanism and discuss why certain mechanisms dominate at specific frequency ranges
h . if this material shows temperature-dependent relative permittivity r=6.0(at 25C),r=4.0(at 125C), Curie temperature (TC):130C, Describe what happens to the material's dielectric properties as it transitions through the Curie temperature.
i. Draw the polarization hysteresis loops at 25C and 175C. Assume the dielectric constant has a linear relationship with temperature. Note: At 175C(above the Curie temperature TC=130C), the material is in the paraelectric phase and exhibits a linear P-E relationship.
Parallel Plate Capacitor Design and Dielectric

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