PART A$)$ A $1\mathrm{.}045$ g solid unknown was extractd using $25\mathrm{.}00$ mL of hexanes. The extract is analysed using GC$-$MS$,$ with an area of $481\mathrm{.}444$ for compound Y$.$ A standard at $0\mathrm{.}4567$ mg$/$L of compound Y had an area of $520\mathrm{.}789.$ Find the mg Y$/$g solid.

PART B$)$ Say another scientist found an answer of $0\mathrm{.}5553$ mg Y$/$g solid. Using the formula $($ppm$=($g Y$)/($g solid$)*10^6),$ convert this to ppm for solids.

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PART A First we need to calculate the concentration of compound Y in ... View the full answer