Phosphine $(P{H}_3)$ can theoretically be made by the reaction of hydrogen gas and red phosphorus by the reaction below. What temperature conditions are required $($above or below what temperature$)$ for the formation of $P{H}_3$ to be favored at standard pressure? $($note that $Hr$ is per mole$)$

$S_r(H_2,g)=+130\mathrm{.}6\frac{J}{m}ol*K$

$S_r(P_4,s(red))=+22\mathrm{.}8\frac{J}{m}ol*K$

$S_r(P{H}_3,g)=+210\mathrm{.}2\frac{J}{m}ol*K$

$6H_2(g)+P_4(s,$ red $)4P{H}_3(g)$

$H(P{H}_3,g)=+5\mathrm{.}4k\frac{J}{m}ol$