Please explain step-by-step.

Q2. (10 pts) What are in the following status register bits and registers after the following instructions? If any memory location's data changes, indicate that. The instructions are executed sequentially. AVR code R16 R17 | R26 R27R28R29 R30R31 S23 S4A S01$02 SFE S01 S04 S02 Given internal SRAM Addresss SRAM New value LD R16,x+ $0200 $0201 $0202 $0203 $0204 $0205 $0206 $B3 $65 $90 $4A FE $21 AF LDD R17,Z+2 EOR R16,R17 ST -Z,R16 STD Y+4,R17 Note: LD R16.X+ After execution: X-X 1 = $0201 + 1 = $0202-R27: R26 R26 = $02 LDD R17,Z+2 means R17DIZ+2]DI$0204 +2]F DIS02061 $AF but Z does not change! ST -Z,R16 means Z-Z-1 $0204 1 $0203 R31:R30R30-$03 and DIS0203] R16 $CA Q2. (10 pts) What are in the following status register bits and registers after the following instructions? If any memory location's data changes, indicate that. The instructions are executed sequentially. AVR code R16 R17 | R26 R27R28R29 R30R31 S23 S4A S01$02 SFE S01 S04 S02 Given internal SRAM Addresss SRAM New value LD R16,x+ $0200 $0201 $0202 $0203 $0204 $0205 $0206 $B3 $65 $90 $4A FE $21 AF LDD R17,Z+2 EOR R16,R17 ST -Z,R16 STD Y+4,R17 Note: LD R16.X+ After execution: X-X 1 = $0201 + 1 = $0202-R27: R26 R26 = $02 LDD R17,Z+2 means R17DIZ+2]DI$0204 +2]F DIS02061 $AF but Z does not change! ST -Z,R16 means Z-Z-1 $0204 1 $0203 R31:R30R30-$03 and DIS0203] R16 $CA