Question: Please explain The complete mechanism for a reaction is considered to occur in two steps, one of which is slow and the other fast: A+BCA+CD+Efastslow

Please explain

Please explain The complete mechanism for a reaction is considered to occur

The complete mechanism for a reaction is considered to occur in two steps, one of which is slow and the other fast: A+BCA+CD+Efastslow What is the rate law predicted by this mechanism? a) Rate =k[A][B] b) Rate =k[A][C] c) Rate =k[A]2[B] d) Rate =k[A][C]2 e) Rate =k[A]2[B][C]

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