Please need an answer asap with steps

da 1. For the integral the appropriate substitution is ... and the resulting trigonometric x2V25 - 22 OA. z = 5 tan(0) 25 J sec 0) 10 tan ? (0 ) OB. T - 5 sin(0) 25 J sin'(0) OC. T = 5 sec(0) J cos(0) de OD. None of these OE. I - 5 sin(0) 1. For the integral the appropriate substitution is .... and the resulting trigonometric integr 12 V2 -9 OA. None of these OB. z = 3 sin(0) 3 / tan(0) de OC. I = 3 sec(0) - J cos(0)de OD. z = 3 sec(0) J sec(0) de OE. x = 3 tan(0) sec(@ de tan- (0 )