Question: Probability Calculation: The critical path for a project was found to be 37 days. The variances total 27. What is probability of completing in 43

Probability Calculation: The critical path for a

Probability Calculation: The critical path for a project was found to be 37 days. The variances total 27. What is probability of completing in 43 days? Below is information that might be useful to answer the question. Answer to 2 decimal points. (D-u) Z= vo D = desired completion time u = critical time, sum of critical path times o = variance of critical path, sum of variances on critical path Z = number of standard deviations Example: the area to the left of Z-1.34 is found by following the left Z column down to 1.3 and moving right to the .04 column. At the intersection read 9099. The area to the right of Z-1.34 is 1 - 9099,0901. The area between the mean (dashed line) and Z-1.34-9099 - 5,4099. Z X .07 5279 .0 .1 2 .3 4 .5 .6 .7 .8 9 1.0 1.1 1.2 1.3 00 5000 .5398 .5793 .6179 .6554 .6915 .7257 .7580 .7881 .8159 .8413 .8643 .8849 .9032 .01 .5040 5438 5832 .6217 .6591 .6950 .7291 .7611 .7910 .8186 .8438 .8665 .8869 .9049 .02 SOSO 5478 5871 .6255 .6628 .6985 .7324 .7642 .7939 .8212 .8461 .8686 .8888 .9066 .03 .5120 .5517 5910 .6293 .6664 .7019 .7357 .7673 .7967 .8238 .8485 .8708 .8907 9082 .04 .5160 .5557 .5948 .6331 .6700 .7054 .7389 .7704 .7995 .8264 .8508 .8729 .8925 .9099 .05 .5199 .5596 .5987 .6368 .6736 .7088 .7422 .7734 .8023 .8289 .8531 .8749 .8944 9115 .06 .5239 .5636 .6026 .6406 .6772 .7123 .7454 .7764 .8051 .8315 .8554 .8770 .8962 .9131 .5675 .6064 .6443 .6808 .7157 .7486 .7794 .8078 .8340 .8577 .8790 .8980 .9147 .08 5319 5714 .6103 .6480 .6844 .7190 .7517 .7823 .8106 8365 .8599 .8810 8997 .9162 .09 5359 .5753 .6141 .6517 .6879 .7224 .7549 .7852 .8133 .8389 .8621 .8880 .9015 .9177 Network Diagram: For the network diagram below, what is the expected project completion time assuming the units are in days? A,4 0,3 F,6 Start End B,3 C, 5 G,6 E,9

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