Question: Probability Calculation: The critical path for a project was found to be 37 days. The variances total 27. What is probability of completing in 43

Probability Calculation: The critical path for a

Probability Calculation: The critical path for a project was found to be 37 days. The variances total 27. What is probability of completing in 43 days? Below is information that might be useful to answer the question. Answer to 2 decimal points. (D-u) Z = 2 4 D = desired completion time u = critical time; sum of critical path times o = variance of critical path; sum of variances on critical path Z = number of standard deviations a Example: the area to the left of Z-1.34 is found by following the left Z column down to 1.3 and moving right to the .04 column. At the intersection read 9099. The area to the right of Z-1.34 is 1-9099,0901. The area between the mean (dashed line) and Z-1.34.9099 - 5,4099. z x $ .02 .03 .06 0 .1 2 4 .5 .6 .7 .8 .9 1.0 1.1 1.2 1.3 00 5000 .5398 .5793 .6179 .6554 .6915 .7257 .7580 .7881 .8159 .8413 .8643 .8849 .9032 .01 .5040 .5438 .5832 .6217 .6591 .6950 .7291 .7611 .7910 .8186 .8438 .8665 .8869 .9049 5080 5478 5871 .6255 .6628 .6985 .7324 .7642 .7939 .8212 .8461 .8686 .8888 .9066 .5120 5517 .5910 .6293 .6664 .7019 .7357 .7673 .7967 .8238 .8485 .8708 .8907 .9082 .04 .5160 .5557 .5948 .6331 .6700 2054 .7054 .7389 .7704 .7995 .8264 .8508 .8729 .8925 .9099 .05 .5199 .5596 .5987 .6368 .6736 .7088 .7422 .7734 .8023 .8289 .8531 .8749 .8944 9115 .5239 .5636 .6026 .6406 .6772 .7123 .7454 .7764 .8051 .8315 .8554 .8770 .8962 .9131 .07 .5279 .5675 .6064 .6443 .6808 .7157 .7486 .7794 .8078 .8340 .8577 .8790 .8980 .9147 .08 5319 5714 .6103 .6480 .6844 .7190 .7517 .7823 .8106 .8365 .8599 .8810 .8997 .9162 .09 .5359 .5753 .6141 .6517 .6879 .7224 .7549 .7852 .8133 .8389 .8621 .8880 9015 .9177 1.4 1.5 .9192 .9332 .9207 9345 9222 .9357 9236 9370 .9251 .9382 .9265 9394 .9279 .9406 .9292 .9418 .9306 .9429 .9319 9441

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